x^2-384x+620=0

Solution for x^2-384x+620=0 equation:

x^2-384x+620=0

a = 1; b = -384; c = +620;
Δ = b2-4ac
Δ = -3842-4·1·620
Δ = 144976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{144976}=\sqrt{16*9061}=\sqrt{16}*\sqrt{9061}=4\sqrt{9061}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-384)-4\sqrt{9061}}{2*1}=\frac{384-4\sqrt{9061}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-384)+4\sqrt{9061}}{2*1}=\frac{384+4\sqrt{9061}}{2}
$